How to skip parents node in css list menu?

I'd use a Universal Viewer vs. CSS List Menu, you have a lot more control. In this case, I believe you can check the hide in menu option in Properties>Navigation on the page and it should do the trick but not sure if it will allow the children to display.

I have tried your way but no lucky. Once parents are not displayed, children are not.

Hi,

what properties did you set on your Universal Viewer? Since Brendens Solution works for me.

Just set the Where condition to DocumentMenuItemHideInNavigation = 0

http://content.screencast.com/users/DavidTK/folders/Jing/media/de0b3d0a-25b8-428b-aa70-d7d27cfba6dc/2016-01-05_1038.png

Hope this helps.

Greets,

David

Hi David,

Yes, The children could be displayed by using Universal Viewer. But how can I create a navigation bar with below format:

<ul>
    <li>Node A</li>    
    <li>Node B    
        <ul>        
            <li>Node B11</li>            
            <li>Node B12</li>                        
            <li>Node B21</li>
            <li>Node B22</li>            
        </ul>        
    </li>    
</ul>

I added a Header Transformation & Footer Transformation (or First Item Transformation & Last Item Transformation) into the Viewer but it render a incorrect format

<ul>
    <li>Node A</li>    
    <li>Node B</li>      
    <li>Node B11</li>            
    <li>Node B12</li>                        
    <li>Node B21</li>
    <li>Node B22</li>
</ul>

Item transformation

<li><%# Eval("NodeName") %></li>

Header Transformation

<ul>

Footer Transformation

</ul>

Child nodes were not displayed since using Hierarchical Transformation